Zigzag Conversion

The string “PAYPALISHIRING” is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: “PAHNAPLSIIGYIR”

Write the code that will take a string and make this conversion given a number of rows:

string convert(string s, int numRows);

Example

• Input: s = “PAYPALISHIRING”, numRows = 4
• Output: “PINALSIGYAHRPI”
• Explanation:

  P     I    N
  A   L S  I G
  Y A   H R
  P     I
  

  Solution (Java)

Been a minute I posted here, sorry for that! This is one typical problem that sounds more complicated as it is. Don’t try to find an algorithmic elegant solution, rather think of a good data structure to make it easier. And by good data structure, I don’t mean that there is one data structure that magically solves this.

The trick is using for each row a list, then you use a variable which points to which list we are writing as we iterate through the string. Obviously it should toggle it’s direction after it reaches the the end/beginning of the lists, similar like a metronome (sorry there’s no metronome emoji).

class Solution {
    public String convert(String s, int numRows) {
        if(numRows == 1){
            return s;
        }
        
        String[] strings = new String[numRows];
        for(int i=0; i<numRows; i++){
            strings[i] = "";
        }

        boolean clockWise = true;
        int n = s.length();
        int id = 0;
        for(int i = 0; i < n; i++){
            char c = s.charAt(i);
            strings[id] += c;

            if(id == 0){
                clockWise = true;
            } else if(id == numRows - 1){
                clockWise = false;
            }

            if(clockWise){
                id++;
            }else{
                id--;
            }
        }

        StringBuilder sb = new StringBuilder("");
        for(int i=0; i<numRows; i++){
            sb.append(strings[i]);
        }

        return sb.toString();
    }
}